Grokking the Coding Interview: Patterns for Coding Questions
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Solution: Factor Combinations

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A

Anonymous

· 2 years ago

from math import sqrt 

class Solution:
  def getFactors(self, n):
    
    def get_number_factors():
      factors = set()
      for i in range(2, int(sqrt(n)) + 1):
        if n % i == 0:
          factors.add(i)
          factors.add(n / i)
      return list(factors)

    def backtrack(result, path, mpy, factors, index):
      if mpy > n:
        return 
        
      if mpy == n and len(path) > 0:
        result.append(path[:])
        return

      for i in range(index, len(factors)):
        mpy *= factors[i]
        path.append(factors[i])
        backtrack(result, path, mpy, factors, i)
        path.pop()
        mpy /= factors[i]
    
    result = []
    factors = get_number_factors()
    backtrack(result, [], 1, factors, 0)

    return result
A

Anonymous

· 2 years ago

.

A

Anonymous

· 3 years ago

Can anyone please explain how the space complexity will be (log n) ?

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