Grokking Dynamic Programming Patterns for Coding Interviews
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Solution: Longest Palindromic Substring
Problem Statement
Given a string, find the length of its Longest Palindromic Substring (LPS). In a palindromic string, elements read the same backward and forward.
Example 1:
Input: "abdbca"
Output: 3
Explanation: LPS is "bdb".
Example 2:
Input: = "cddpd"
Output: 3
Explanation: LPS is "dpd".
Example 3:
Input: = "pqr"
Output: 1
Explanation: LPS could be "p", "q" or "r".
Constraints:
1 <= st.length <= 1000stconsists only of lowercase English letters.
Basic Solution
This problem follows the "Longest Palindromic Subsequence" pattern
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A
Anonymous
· 2 years ago
class Solution: def findCPS(self, st): def is_palindrom(s, i, j): while i <= j : if s[i] != s[j]: return False i += 1 j -= 1 return True count = 0 for i in range(0, len(st)): for j in range(i, len(st)): if is_palindrom(st, i, j): count += 1 return count
A
Anonymous
· 4 years ago
Can you add the brute force, swapping the max for count does not work on the leetcode problem
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