Problem 3: Maximum Number of Balloons (easy)

        c = Counter(text)

        min_count = min([c.get('b', 0), c.get('a', 0), c.get('l', 0) // 2, c.get('o', 0) // 2, c.get('n', 0)])
        return min_count

from collections import Counter

class Solution:
    def maxNumberOfBalloons(self, text: str) -> int:
        min_count = float('inf')

        balloon_counter = Counter('balloon')    
        text_counter = Counter(text)

        for char, freq in balloon_counter.items():
            if char not in text_counter:
                return 0
            else:
                min_count = min(min_count, text_counter[char] // freq)

        return min_count