Problem 2: Remove Duplicates from Sorted List (easy)

class Solution:
    def deleteDuplicates(self, head):
        # so I dont lose my original head, I set a variable current
        current = head
        # traverse through LL, ensuring curr and curr.next exist
        while current and current.next is not None:
            # prev becomes the value to which we compare other values to
            prev = current
            current = current.next
            # we move current until current.val no longer matches prev value
            # ensure we don't hit None by checking that current also exists
            while current and prev.val == current.val:
                current = current.next
            # whether current is now None or some number that is not prev.val, we set prev.next
            prev.next = current
        return

Kindly add the main method and print method to avoid confusion and add clarity.

public void printList(ListNode head) {
    ListNode current = head;
    while (current != null) {
        System.out.print(current.val + " ");
        current = current.next;
    }
    System.out.println();
}

public static void main(String[] args) {
    Solution solution = new Solution();
    
    // Test Example 1
    ListNode head1 = new ListNode(1, new ListNode(1, new ListNode(2)));
    ListNode result1 = solution.deleteDuplicates(head1); // Expected: 1 -> 2
    solution.printList(result1);

    // Test Example 2
    ListNode head2 = new ListNode(1, new ListNode(2, new ListNode(2, new ListNode(3))));
    ListNode result2 = solution